glass wool · 150mm
R 4.05
U 0.237 W/m²·K
glass wool, 150 mm — R 4.05
150 mm divided by a conductivity of 0.037 gives an R-value of 4.05. The U-value is 0.237, so a square metre leaks 4.73 W across a 20-degree difference.
Standards it meets
- loose standard 0.30
- Material
- glass wool
- Thickness
- 150 mm
- Thermal conductivity
- 0.037 W/m·K
- Thermal resistance
- 4.05 m²·K/W
- U-value
- 0.237 W/m²·K
- Heat lost per square metre
- 4.73 W
- As concrete
- 6.49 m
Thickness for the same performance
This is the number that shows what insulation is worth. Matching 100 mm of XPS with concrete alone would take 5.7 metres of it. No one builds a wall like that — which is why a concrete building only gets warm once a thin layer of insulation is added.
- vacuum panel28 mm
- phenolic foam81 mm
- rigid polyurethane93 mm
- extruded polystyrene114 mm
- graphite EPS126 mm
- white EPS146 mm
- mineral wool162 mm
- cellulose170 mm
- timber527 mm
- plasterboard730 mm
- concrete6486 mm
Nearby cells
Same material, other thicknesses
Same thickness, other materials
How to read this
- Thermal resistance is the thickness in metres divided by the conductivity. Bigger is better.
- The U-value adds 0.17 of surface resistance and then flips the total. Smaller is better.
- Resistances add across layers, so a whole wall is the sum of its parts.
- Conductivity varies by product; the values here are typical for the material.
Frequently asked questions
Q. What is the R-value of 150 mm of glass wool?
4.05 — 150 mm in metres divided by a conductivity of 0.037.
Q. And the U-value?
0.237. That is 4.22 — the resistance plus 0.17 of surface — turned upside down, and a square metre leaks 4.73 W across 20 degrees.
Q. How much concrete would match it?
6.49 metres.
Q. Which standards does it meet?
At 0.237 it clears 1 of them.